Quantitative Aptitude Quiz For SBI PO/Clerk Prelims
Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions
Directions (1-5): Study the following information carefully and answer the questions given beside.
Three friends Seeta, Reeta and Geeta spends 12%, 14% and 16% of their monthly salary on travelling in the given order and each of them save half of the remaining amount. The monthly salary of Seeta and Geeta is same and the monthly saving of Seeta is Rs. 360 more than that of Geeta. The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.
Q1. What is the monthly expenditure of Seeta and Reeta together on travelling?
Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x
Remaining = Rs. (100x – 12x) = Rs. 88x
Saving = 88x/2 = Rs. 44x
Reeta’s month salary = Rs. 100y
Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y
Remaining = Rs. (100y – 14y) = Rs. 86y
Saving = 86y/2 = Rs. 43y
The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x
The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x
Remaining = Rs. (100x – 16x) = Rs. 84x
Saving = 84x/2 = Rs. 42x
The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta
44x – 42x = 2x = 360
x = 180
The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.
12x + 14y = 16x + 1240
14y = 4x + 1240 = 720 + 1240 = 1960
y = 140
The monthly expenditure of Seeta and Reeta together on travelling = Rs. (12x + 14y) = Rs. (12 × 180 + 14 × 140)
= Rs. (2160 + 1960) = Rs. 4120
Q2. The monthly salary of Reeta is how much more than/less than that of Seeta?
Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x
Remaining = Rs. (100x – 12x) = Rs. 88x
Saving = 88x/2 = Rs. 44x
Reeta’s month salary = Rs. 100y
Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y
Remaining = Rs. (100y – 14y) = Rs. 86y
Saving = 86y/2 = Rs. 43y
The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x
The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x
Remaining = Rs. (100x – 16x) = Rs. 84x
Saving = 84x/2 = Rs. 42x
The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta
44x – 42x = 2x = 360
x = 180
The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.
12x + 14y = 16x + 1240
14y = 4x + 1240 = 720 + 1240 = 1960
y = 140
The monthly salary of Reeta = Rs. 100y = Rs. 14000
The monthly salary of Seeta = Rs. 100x = Rs. 18000
The required answer = Rs. (14000 – 18000) = 4000 less than that of Seeta
Q3. What is the sum of the saving of all the three friends together?
Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x
Remaining = Rs. (100x – 12x) = Rs. 88x
Saving = 88x/2 = Rs. 44x
Reeta’s month salary = Rs. 100y
Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y
Remaining = Rs. (100y – 14y) = Rs. 86y
Saving = 86y/2 = Rs. 43y
The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x
The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x
Remaining = Rs. (100x – 16x) = Rs. 84x
Saving = 84x/2 = Rs. 42x
The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta
44x – 42x = 2x = 360
x = 180
The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.
12x + 14y = 16x + 1240
14y = 4x + 1240 = 720 + 1240 = 1960
y = 140
The required sum = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500
Q4. The total monthly saving of three friends together is what percentage of their total monthly salary?
Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x
Remaining = Rs. (100x – 12x) = Rs. 88x
Saving = 88x/2 = Rs. 44x
Reeta’s month salary = Rs. 100y
Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y
Remaining = Rs. (100y – 14y) = Rs. 86y
Saving = 86y/2 = Rs. 43y
The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x
The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x
Remaining = Rs. (100x – 16x) = Rs. 84x
Saving = 84x/2 = Rs. 42x
The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta
44x – 42x = 2x = 360
x = 180
The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.
12x + 14y = 16x + 1240
14y = 4x + 1240 = 720 + 1240 = 1960
y = 140
Their total monthly salary = Rs. (100x + 100y + 100x) = Rs. (200x + 100y) = Rs. (36000 + 14000) = Rs. 50000
Total monthly saving = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500
The reqd. answer =
= 43%
Q5. By how much should Seeta's monthly salary be increased so the monthly expenditures of Seeta on travelling will become equal to that of Geeta?
Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x
Remaining = Rs. (100x – 12x) = Rs. 88x
Saving = 88x/2 = Rs. 44x
Reeta’s month salary = Rs. 100y
Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y
Remaining = Rs. (100y – 14y) = Rs. 86y
Saving = 86y/2 = Rs. 43y
The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x
The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x
Remaining = Rs. (100x – 16x) = Rs. 84x
Saving = 84x/2 = Rs. 42x
The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta
44x – 42x = 2x = 360
x = 180
The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.
12x + 14y = 16x + 1240
14y = 4x + 1240 = 720 + 1240 = 1960
y = 140
Let the monthly salary of Seeta was increased by Rs a then,
12% × (18000 + a) = 16% × 18000
3 × (18000 + a) = 4 × 18000
a = Rs 6000
Directions (6-8): In the following questions two quantities are given for each question. Compare the numeric value of both the quantities and answers accordingly.
Q6. Quantity 1: No. of five digits number which can be formed using the digits 1, 3, 4, 5, 6, 7 without repetition of digits.
Quantity 2: Length of platform. Speed of a train is 90 km/h. It crosses a platform and a pole in 36 seconds and 6 seconds respectively.
Q7. Quantity 2: Time in which the tank will be filled from start. A tap ‘A’ can fill a cistern in 12 hours while another tap B can empty the filled tank in 18 hours. If both pipes are opened together and after 3 hours tap B is closed.
Quantity 1: A man covers half of total distance with 12 km/h and another half distance with 24km/h. Find his average speed.
Q8. Quantity1: Ravi can do three fourth of a work in 27/2 hours while Hira can do two third of the same work in 8 hours. If both started working together then in how much time the work will be completed?
Quantity 2: Raju’s age before two years was 75% of his sister, Rita’s age. After two years, Rita’s age will be
of her father’s age. Average age of Rita’s father and mother is 31 yrs. If Rita’s mother’s age is 28 yrs then what is the present age of Raju?
Directions (9-15): What will come in place of the question mark (?) in the following questions?
Q9.
Q10.
Q11.
Q12.
Q13. 36% of 245 – 40% of 210 = 10 –?
Q14. 4345 + 5625 + 7125 – 3345 = ?
Q15.
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