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SBI PO Quantitative Aptitude Quiz: 5th May 2019

Dear Aspirants,


SBI-PO-Quantitative-Aptitude-Quiz

Quantitative Aptitude Quiz For SBI PO/Clerk Prelims


Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.




Directions (1-5): In the following line graph, the production of cars by three different companies is given in six different years. Study the graph carefully and answer the related questions. 


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Q1. What is the approximate percentage increase in production of cars by company B in 2015 than previous year?

50.5%
45.45%
55%
40%
55.55%
Solution:

SBI PO Quantitative Aptitude Quiz: 5th May 2019 |_4.1

Q2. Find the difference between average production of cars by company A and that of company C throughout all the years.

5 lakhs
5.4 lakhs
4.6 lakhs
6.6 lakhs
5.6 lakhs
Solution:

SBI PO Quantitative Aptitude Quiz: 5th May 2019 |_5.1

Q3. Production of cars made by company A in 2012 and 2013 together is what percent of total cars made by company B over all the years? (approximately)

35%
33%
28%
46%
25%
Solution:

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Q4. Find the ratio of cars produced by company-C in years 2012 and 2015 together to that of the cars produced by company-B in the years 2014 and 2016 together.

21 : 23
27 : 29
29 : 23
23 : 29
33 : 23
Solution:

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Q5. If production of cars by company-A increases by 10% in 2017 than previous year, then find the new average production of cars by company –A over all the years including the year 2017.

32.5 lakhs
35 lakhs
28.5 lakhs
30.5 lakhs
None of these
Solution:

SBI PO Quantitative Aptitude Quiz: 5th May 2019 |_8.1

Q6. A shopkeeper buys 144 items at 90 paise each. On the way 20 items are broken. He sells the remainder at Rs. 1.20 each. His gain per cent correct to one place of decimal is

13.8%
14.6%
14.8%
15.8%
None of these
Solution:

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Q7. The ratio of the number of boys and girls in a school is 2 : 3. If 25% of the boys and 30% of the girls are scholarship holders, the percentage of the school students who are not scholarship holders is

72%
36%
54%
60%
None of these
Solution:

SBI PO Quantitative Aptitude Quiz: 5th May 2019 |_10.1

Q8. A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours and 30 minutes. The speed of the boat in still water is

8 km/hr
9 km/hr
12 km/hr
10 km/hr
None of these
Solution:

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Q9. A takes three times as long as B and C together to do a job. B takes four times as long as A and C together to do the work. If all the three, working together can complete the job in 24 days, then the number of days, A alone will take to finish the job is

100
96
95
90
None of these
Solution:

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Q10. 20 litres of a mixture contains 20% alcohol and the rest water. If 4 litres of water be mixed in it, the percentage of alcohol in the new mixture will be

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Solution:

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Directions (11-15): In these questions, two equations numbered I and II are given. You have to solve both the equations and give answer: 


Q11. I. x² – 9x + 18 = 0
 II. 5y² – 22y + 24 = 0

if x < y
if x > y
if x ≤ y
if x ≥ y
if relationship between x and y cannot be determined
Solution:

I. x² – 9x + 18 = 0
x² – 6x – 3x + 18 = 0
x (x – 6) –3 (x -6) = 0
(x – 3) (x – 6) = 0
x= 3, 6
II. 5y² – 22y + 24 = 0
5y² – 10y – 12y + 24 = 0
5y (y- 2) –12 (y – 2) = 0
(y – 2) (5y – 12) = 0
y = 2, 12/5
∴ x > y

Q12. I. 6x² + 11x + 5 = 0 
II. 2y² + 5y + 3 = 0

if x < y
if x > y
if x ≤ y
if x ≥ y
if relationship between x and y cannot be determined
Solution:

I. 6x² + 11x + 5 = 0
6x² + 6x + 5x + 5 = 0
6x (x + 1) + 5 (x + 1) = 0
(x+ 1) (6x +5) = 0
x=-1,-5/6
II. 2y² + 5y + 3 = 0
2y² + 2y + 3y + 3 = 0
2y (y+ 1) + 3 (y+ 1) = 0
(y+ 1) (2y + 3) = 0
y= -1,-3/2
∴x≥y

Q13. I. x² + 10x + 24 = 0 
II. y² – √625=0

if x < y
if x > y
if x ≤ y
if x ≥ y
if relationship between x and y cannot be determined
Solution:

I. x² + 10x + 24 = 0
x² +6x + 4x + 24 = 0
x (x + 6) +4 (x+ 6) = 0
(x + 4) (x + 6) = 0
x = –4, –6
II. y² – √625=0
y²=√625
y² = 25;
y= ±5
∴ Relationship between x and y cannot be determined

Q14. I. 10x² + 11x + 1 = 0 
II. 15y² + 8y + 1 = 0

if x < y
if x > y
if x ≤ y
if x ≥ y
if relationship between x and y cannot be determined
Solution:

I. 10x² +11x + 1= 0
10x² + 10x+ x+ 1 = 0
10x (x + 1) + 1 (x + 1) = 0
(x + 1) (10x + 1) = 0
x= -1,-1/10
II. 15y² + 8y + 1 = 0
15y² +5y + 3y + 1 = 0
5y (3y + 1) + 1 (3y+ 1) = 0
(3y + 1) (5y + 1) = 0
 y=-1/3,-1/5
 ∴ Relationship between x and y cannot be determined

Q15. I.15x² – 11x + 2 = 0 
II. 10y² – 9y + 2 = 0

if x < y
if x > y
if x ≤ y
if x ≥ y
if relationship between x and y cannot be determined
Solution:

I. 15x² – 11x + 2 = 0
15x² – 5x – 6x + 2 = 0
5x (3x – 1) – 2 (3x – 1) = 0
(3x – 1) (5x – 2) = 0
x=1/3,2/5
II. 10y² – 9y + 2 = 0
10y² – 5y – 4y + 2 = 0
5y (2y – 1) –2 (2y – 1) = 0
(2y – 1) (5y - 2) =0
 y=1/2,2/5
∴ x ≤ y

               




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