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SBI PO Quantitative Aptitude Quiz: 27th April

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Quantitative Aptitude Quiz For SBI PO/Clerk Prelims

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.




Q1. A mixture contains milk and water in the ratio 5 : 1. On adding 5 liters of water, the ratio of milk and water becomes 5 : 2. The quantity of milk in the original mixture is?

16 litres
25 litres
22.75 liters
32.5 liters
28 litres
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_3.1

Q2. A vessel contains 1 litre mixture of kerosine and disel and the other vessel contains 2 litre mixture of the same. The ratio of kerosine and disel in first and second vessels is 5 : 4 and 7 : 2 respectively. The mixture of second vessel is poured into first vessel. Find the ratio of kerosine to disel in the first vessel.

8 : 11
9 : 8
19 : 8
11 : 19
11 : 8
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_4.1

Q3. A chemist has 10 litre of a solution that is 10% sulphuric acid by volume. He wants to dilute the solution to 4% strength by adding water how many litre of water must be added?

15 litre
20 litre
18 litre
25 litre
17 litre
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_5.1

Q4. Rishabh bought 25 kg of wheat at the rate of Rs. 6 per kg and 35 kg of wheat at the rate of Rs. 7 per kg. He mixed both type of wheat and sold the mixture at the rate of Rs. 6.75 per kg. What was his gain or loss in the transaction?

Rs. 16, gain
Rs. 16, Loss
Rs. 20, gain
Rs. 10, gain
Rs. 10, loss
Solution:

gain in the transaction
 = 6.75 × 60 – (25 × 6 + 35 × 7)
 = Rs. 10, gain

Q5. An alloy contains silver and lead in the ratio 5 : 8 and another alloy contains silver and lead in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of silver to lead in the resulting alloy is

25 : 24
3 : 8
103 : 105
105 : 103
8 : 3
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_6.1

Directions (6-10): In each of the following questions two equations are given. You have to solve the equations and
Give answer – 



Q6. I. 3x² + 16x + 21 = 0 
II. 6y² + 17y + 12 = 0

if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:

I. 3x² + 16x + 21 = 0
⇒ 3x² + 9x + 7x + 21 = 0
⇒ (x + 3) (3x + 7) = 0
⇒ x = –3, –7/3
II. 6y² + 17y + 12 = 0
⇒ 6y² + 9y + 8y + 12 = 0
⇒ 3y (2y + 3) + 4 (2y + 3) = 0
⇒ y = – 3/2, –4/3
y > x

Q7. I. 16x² + 20x + 6 = 0 
 II. 10y² + 38y + 24 = 0

if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:

I. 16x² + 20x + 6 = 0
⇒ 8x² + 10x + 3 = 0
⇒ 8x² + 4x + 6x + 3 = 0
⇒ (2x + 1) (4x + 3) = 0
⇒ x = –1/2, –3/4
II. 10y² + 38y + 24 = 0
⇒ 5y² + 19y + 12 = 0
⇒ 5y² + 15y + 4y + 12 = 0
⇒ (y + 3) (5y + 4) = 0
y = –3, –4/5
x > y

Q8. I. 8x² + 6x = 5 
 II. 12y² – 22y + 8 = 0

if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:

I. 8x² + 6x – 5 = 0
⇒ 8x² + 10x – 4x – 5 = 0
⇒ (4x + 5) (2x – 1) = 0
⇒ x = ½, –5/4
II. 12y² – 22y + 8 = 0
⇒ 6y² – 11y + 4 = 0
⇒ 6y² – 3y – 8y + 4 = 0
⇒ (2y – 1) (3y – 4) = 0
⇒ y = 1/2, 4/3
y ≥ x

Q9. I. 17x² + 48x = 9 
 II. 13y² = 32y – 12

if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:

I. 17x² + 48x – 9 = 0
⇒ 17x² + 51x – 3x – 9 = 0
⇒ (x + 3) (17x – 3) = 0
⇒ x = 3/17, – 3
II. 13y² – 32y + 12 = 0
⇒ 13y² – 26y – 6y + 12 = 0
⇒ (y – 2) (13y – 6) = 0
⇒ y = 2, 6/13
y > x

Q10. I. 8x² + 26x + 15 = 0 
 II. 4y² + 24y + 35 = 0

if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:

I. 8x² + 26x + 15 = 0
⇒ 8x² + 20x + 6x + 15 = 0
⇒ 4x (2x + 5) + 3(2x + 5) = 0
⇒ (2x + 5) (4x + 3) = 0
⇒ x = – 5/2, –3/4
II. 4y² + 24y + 35 = 0
⇒ 4y² + 10y + 14y + 35 = 0
⇒ 2y (2y + 5) + 7 (2y + 5) = 0
⇒ (2y + 5) (2y + 7) = 0
⇒ y = –5/2, –7/2
x ≥ y

Directions (11 – 15): Read the following graph carefully and answer the questions given below 


Percentage distribution of total number of students who completed their graduation from different Universities A, B, C, D, E and F.

SBI PO Quantitative Aptitude Quiz: 27th April |_7.1



Q11. The number of males in university D is equal to number of females of which university?

C
A
F
E
None of these
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_8.1

Q12. What is the respective ratio between number of males in university B and number of females in university F?

2:1
3:2
3:1
2:3
None of these
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_9.1

Q13. The number of males in university A is what percent of total number of students in university E?

74
72
78
70
None of these
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_10.1

Q14. What is the total number of females in all universities together?

15045
15050
15030
15020
15040
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_11.1

Q15. The number of males in university C is approximately what percent more than the number of males in university F?

152
167
163
159
155
Solution:

SBI PO Quantitative Aptitude Quiz: 27th April |_12.1

               

SBI PO Quantitative Aptitude Quiz: 27th April |_13.1




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