SBI Clerk Quantitative Aptitude Quiz: 11th May 2019

Quantitative Aptitude Quiz For SBI PO/Clerk Prelims

Directions (1-5): Simplify the following problems. 


Q1. 56% of 958 + 67% of 1008 = ?% of 2000

Solution:

Q2.

Q3. (47 × 588) ÷ (28 × 120) = ?

Solution:

Q4.

Solution:

Q5. 74156 – ? – 321 – 20 + 520 = 69894

Q6. The average age of Priya and Pooja is 18 years. When Nancy replaces Pooja, the average age is increased by 1 and when Pooja replaces Priya the average age becomes 17 years. What is the age of Nancy?

Solution:

Q7. Rohit earns an interest of Rs. 1,656 for the third year and Rs. 1,440 for the second year on the same sum. Find the rate of interest if it is lent at compound interest at annually.

Solution:

Q8. The average of five consecutive even numbers is 28. What is difference between squares of largest number and second smallest number ?

Solution:

Q9. Two equal sums were lent, one at the rate of 11% p.a. for five years and the other at the rate of 8% p.a. for six years, both under simple interest. If the difference in interest accrued in the two cases is Rs 1008. Find the sum.

Solution:

Q10. The ratio of the capitals lent for two years under CI annually and for four year under SI is 6: 5 given that the rate of interest for both is same. When the interest obtained is same, then the value of the rate of interest is

Solution:

Directions (11-15): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer 


Q11. I. x² + 5x + 6 = 0 
II. y² + 3y + 2 = 0

Solution:

Q12. I. 4x² - 8x + 3 = 0 
II. 2y² - 7y + 6 = 0

Solution:

Q13. I. 4x + 2y = 51 
II. 15y + 13x = 221

Solution:

Q14. I. x² - 14x + 48 = 0 
II. y² + 6 = 5y

Solution:

Q15. I. x² - 1 = 0 
II. y² + 4y + 3 = 0

Solution: