Q1. If it is possible to make a meaningful word from 1st, 3rd, 5th, 7th and 11th letters of the word “EXASPERATION“, then which will be the 1st letter of that meaningful word? If more than one such meaningful words can be formed then ‘W’ is your answer. If no such meaningful word is formed, then ‘X’ is your answer.
(a) W
(b) A
(c) P
(d) O
(e) X
Q2. If it is possible to make a meaningful word from 3rd, 7th, 8th, 9th and 11th letters of the word “SURROUNDING“, then which will be the last letter of that meaningful word? If more than one such meaningful words can be formed then ‘W’ is your answer. If no such meaningful word is formed, then ‘X’ is your answer.
(a) W
(b) D
(c) I
(d) G
(e) X
Q3. If it is possible to make a meaningful word from 2nd, 5th, 6th, 8th, 9th, 11th and 12th letters of word “LOBORIOUSNESS“, then which will be the 6th letter of that meaningful word? If more than one such meaningful word can be formed then ‘Y’ is your answer. If no such meaningful word is formed, then ‘X’ is your answer.
(a) S
(b) U
(c) I
(d) Y
(e) X
Q4. If all the consonants of the word “SEPTEMBER” are replaced by their immediately preceding letter & vowels to their immediately following letter according to alphabetical series, then how many vowels will be there in the new rearranged word?
(a) Two
(b) Three
(c) Four
(d) Five
(e) None of the above
Q5. Which of the following letter will be the exactly middle letter, if all the letters of the word “VISHAKAPATNAM” are arranged in reverse alphabetical order from right to left?
(a) M
(b) K
(c) I
(d) H
(e) None of the above
Q6. Which of the following letter will be exactly middle letter, if the letters at odd positions are replaced by their succeeding letter in the word “PARALYSIS“?
(a) M
(b) A
(c) Y
(d) T
(e) None of the above
Q7. How many pairs of letters are there in the word “MELORA” which has as many letters between them as in the alphabetical series (both forward and backward direction)?
(a) One
(b) Two
(c) Three
(d) Four
(e) None of the above
Q8. How many pairs of letters are there in the word “SMYTTEN” which has as many letters between them as in the alphabetical series (both forward and backward direction)?
(a) None
(b) One
(c) Two
(d) Three
(e) Four
Q9. How many pairs of letters are there in the word “BLINKIT” which has as many letters between them as in the alphabetical series (both forward and backward direction)?
(a) None
(b) One
(c) Two
(d) Three
(e) Four
Q10. If each vowel of the word ‘FASHION’ is changed to its next letter and each consonant is changed to its previous letter according to English alphabetical series, after that, the alphabets thus formed are arranged in alphabetical order from left to right, then which of the following will be fifth letter from the left?
(a) P
(b) G
(c) M
(d) J
(e) None of the above
Solutions
S1. Ans. (d)
Sol. 1st, 3rd, 5th, 7th and 11th letters of the given word are E, A, P, R, O. So, the word OPERA can be formed. Hence, ‘O’ will be the first letter of the word.
S2. Ans. (b)
Sol. 3rd, 7th, 8th, 9th and 11th letters of the given word are R, N, D, I and G. So, the word GRIND can be formed. Hence, Last letter of the word is ‘D’.
S3. Ans. (b)
Sol. 2nd, 5th, 6th, 8th, 9th, 11th and 12th letters of the given word are O, R, I, U, S, E and S. So, the word formed is SERIOUS. Hence, the 6th letter of the word is ‘U’.
S4. Ans. (a)
Sol. Consonants are replaced by their previous letter and vowels to their next letter i.e., There are two vowels in the new rearranged word. Hence, option (a) is the answer.
S5. Ans. (b)
Sol. If we arrange the letters in reverse alphabetical order from right to left, then we would get the following word So, the middle letter is K.
S6. Ans. (a)
Sol. If we replaced odd positioned letters with their succeeding letters, then we would get the respective word So, the middle letter will be M.
S7. Ans. (a)
Sol.
S8. Ans. (a)
Sol. There is no pair.
S9. Ans. (c)
Sol.
S10. Ans. (c)
Sol. The rearranged word for FASHION is Thus, M will be 5th from the left.