Dear Aspirants,
Reasoning Quiz for IBPS PO Mains 2018
Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. The only way to make the grade in this particular section in the forthcoming banking exams like IBPS PO Mains is to practice continuously with all your heart and soul. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the exact same pattern of questions that are being asked in the exams.
Direction (1-5): Study the following information carefully and answer the questions given below:
There are ten members P, U, T, R, Q, A, B, D, F, C in a family, all are seated in 2 parallel rows (but not necessarily in the same order). Among them only three married couples. P, U, T, R, Q are seated in row-1 and all are facing to the south. A, B, D, F, C are seated in row-2 and all are facing to the north. Therefore, in the given seating arrangement each member seated in a row faces another member of the other row.
T and his brother are immediate neighbors of each other. Two persons sit between B’s father and Q. P is father of B, who is uncle of T. R is brother-in-law of Q. T and R are children of F’s wife. B sits 2nd to the right of his sister-in-law and B does not sit at extreme end. Aunt of R doesn’t face T’s sister-in-law and T. Q and U are sisters. Husband of C has only 2 grandchildren. Father-in-law of A has only 2 sons and one daughter. Q is daughter-in-law of A and faces her father-in-law who sits 2nd from the right end of the row.
Q1. Who sits 2nd to the left of F’s mother?
A’s sister-in-law
A’s brother-in-law
R’s uncle
Both b and c
None of these
Solution:
To solve such kind of questions first we have to try to make family tree with the help of given conditions,
T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.
Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.
Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.
Q2. Which of the following is F’s position with respect to B?
3rdto the right
2nd to the left
Immediate right
Immediate left
None of these
Solution:
To solve such kind of questions first we have to try to make family tree with the help of given conditions,
T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.
Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.
Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.
Q3. Which of the following is the combination of male members in the family?
PFTRA
PFTRB
TRBFA
None of these
Cannot be determined
Solution:
To solve such kind of questions first we have to try to make family tree with the help of given conditions,
T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.
Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.
Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.
Q4. Which of the following is true?
D is daughter of A
B is brother of A
Both d and e
A is wife of F
F has two sons
Solution:
To solve such kind of questions first we have to try to make family tree with the help of given conditions,
T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.
Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.
Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.
Q5. Which of the following is Q's position with respect to R?
Second to the right
Second to the left
Third to the left
Cannot be determined
None of these
Solution:
To solve such kind of questions first we have to try to make family tree with the help of given conditions,
T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.
Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.
Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.
Directions (6-10): Study the following information carefully and answer the given questions.
A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement.
Input: 14 use 65 robot 27 apple 12 train 25 20 lack melody 15 acute.
Step I: 12 zuse 14 65 robot 27 apple train 25 20 lack melody 15 acute
Step II: 14 atrain 12 zuse 65 robot 27 apple 25 20 lack melody 15 acute
Step III: 15 arobot 14 atrain 12 zuse 65 27 apple 25 20 lack melody acute
Step IV: 20 amelody 15 arobot 14 atrain 12 zuse 65 27 apple 25 lack acute
Step V: 25 alack 20 amelody 15 arobot 14 atrain 12 zuse 65 27 apple acute
Step VI: 27 zapple 25 alack 20 amelody 15 arobot 14 atrain 12 zuse 65 acute
Step VII: 65 zacute 27 zapple 25 alack 20 amelody 15 arobot 14 atrain 12 zuse.
Step VII is the last step of the above arrangement.
As per the rules followed in the steps given above, find out in each of the following questions the appropriate step for the given input.
Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.
Q6. In which step are the elements ‘aharm zout abeyond zupper 11 33’ found in the trend order?
Fifth
Seventh
Fourth
Sixth
There is no such step
Solution:
Number and letter both are arrange from left hand side together.
Pick a number in ascending order and word in descending order.
Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.
Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.
Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out
Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out
Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out
Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20
Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23
Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit
Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit
Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper
Step VIII is the last step of the above arrangement.
Q7. How many words or numbers are there between ‘intense’ and ‘33’ as they appear in the third step of the output?
Six
Three
Four
Two
Seven
Solution:
Number and letter both are arrange from left hand side together.
Pick a number in ascending order and word in descending order.
Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.
Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.
Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out
Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out
Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out
Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20
Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23
Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit
Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit
Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper
Step VIII is the last step of the above arrangement.
Q8. How many steps will be required to complete the above input?
Eight
Six
Five
Seven
None of these
Solution:
Number and letter both are arrange from left hand side together.
Pick a number in ascending order and word in descending order.
Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.
Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.
Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out
Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out
Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out
Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20
Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23
Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit
Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit
Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper
Step VIII is the last step of the above arrangement.
Q9. Which of the following represents the position of ‘8’ in the last but one step?
Ninth from the left end
Fourth from the right end
Thirteenth from the left end
Sixth from the right end
Both (b) and (c)
Solution:
Number and letter both are arrange from left hand side together.
Pick a number in ascending order and word in descending order.
Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.
Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.
Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out
Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out
Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out
Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20
Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23
Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit
Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit
Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper
Step VIII is the last step of the above arrangement.
Q10. In the fifth step of the rearrangement, ‘23’ is related to ‘20’and ‘admit’ is related to ‘zintense’ in a certain way. Which of the following would ‘11’ be related to, following the same pattern?
upper
50
out
28
None of these
Solution:
Number and letter both are arrange from left hand side together.
Pick a number in ascending order and word in descending order.
Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.
Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.
Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out
Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out
Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out
Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20
Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23
Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit
Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit
Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper
Step VIII is the last step of the above arrangement.
Directions (11-12): Read the following information carefully and answer the questions given below:
First 12 numbers are written from bottom to top. The letters of word ‘BEAUTY’ are written in alphabetical order against each multiple of 2 (One letter against one number) from bottom to top. There are 2 letters between E and R. There are as many letters between V and Q as between V and H. There are 3 letters between R and V. R is not against number 9. M is above G and Q is above V (No letter is repeated against any number).
Q11. Which is the second letter in word formed by letters against numbers 3, 6, 7, and 12?
E
V
N
Y
R
Solution:
Letters written against numbers 3, 6, 7, 12 are—R, E, V, Y.
Word formed—VERY. So letter is E.
Q12. Which alphabet is written against no.11?
E
U
Q
M
H
Solution:
“M”
Q13. Pointing to A and B, C says, “Both are the children of the only son of my grandfather.” If A says, “I have as many brothers and sisters as C have.” Then how is B related to D, who is a member of C’s family?
Can’t say
Brother
Sister
Either brother or sister
None of these
Q14. If A is brother of K and K is married to J. F is the mother of J and Y is the only child of K. M is married to Y and son-in-law of K. J is son-in-law of N. Then how is Y related to F?
Daughter-in-law
Granddaughter
Daughter
Can’t be determined
Sister
Solution:
Q15. There are 56 students in a class and the ratio of Boys and Girls are 5:3. Raman’s rank is 16th from the top and there are only 9 boys sitting in between Raman and Shalini, who is a girl and sitting behind Raman. Then how many girls are sitting ahead of Shalini?
15
7
9
Can’t be determine
None of these
Solution:
Total no. of student=56
Boys: Girls=5:3, So Boys=35 and Girls=21
We don’t know the exact number of girls sitting ahead or behind Shalini, so can’t be determine.
The Hindu Review October 2022: Download ...
SSC Calendar 2025-26 Out, Check SSC CGL,...
IRDAI Assistant Manager Score Card 2024 ...
