Directions (1-5): Study the table given below & answer the question.
Table given below shows the number of items sold by four different sellers in the five different months.
Note- Some data are missing in the given table, find the missing data if necessary.
Q1. If seller A sold 150 items in January and February together and number of items sold by seller A in February and March together is 80% of the no. of items sold by same seller in May and June together then find no. of items sold in January by seller A?
(a) 108
(b) 132
(c) 126
(d) 92
(e) 96
Q2. If the ratio of total items sold by seller B in Feb & March together to total items sold by seller C in April & may together is 1 : 2 and items sold by C in May is 64. Then find total items sold by seller B in march?
(a) 14
(b) 20
(c) 24
(d) 12
(e) 32
Q3. If average of items sold in April by all sellers is equal to average items sold in March by all sellers then total items sold by seller B in March is what percent of items sold by seller A in May?
(a) 40%
(b) 50%
(c) 70%
(d) 75%
(e) 60%
Q4. If no. of items sold by seller D in June is 50% more than no. of items sold by seller B in May then find the difference of total items sold by seller D in May & June together and total items sold by seller A in march & April together?
(a) 58
(b) 32
(c) 36
(d) 42
(e) 48
Direction (6-10): Find out the value of question mark (?) in the given questions.
Q6. 12.50% of 1440 – 17×51+721 =?
(a) 30
(b) 31
(c) 32
(d) 33
(e) 34
Q10. (33 + 6.25% of 4096) = ? + 2 × 119
(a) 41
(b) 51
(c) 61
(d) 31
(e) 81
Direction (11–15): Solve the given quadratic equations and mark the correct option based on your answer.
(a) if x>y
(b) if x≥y
(c) if x<y
(d) if x ≤y
(e) if x = y or no relation can be established between x and y.
Q11. I. x2 + 25x+156=0
II. y2 +18y+77=0
Q12. I. x2 +15x – 126 = 0
II. y2 + 13y + 42 = 0
Q13. I. 2×2 – x -45 =0
II. y2 -5y+6=0
Q14. I. x3 – 3375 = 0
II. 3y2 – 675 = 0
Q15. I. x2 – 23x+132= 0
II. 3y2 +16y+21=0
Solutions