Quantitative Aptitude Quiz For IBPS Clerk Main
Directions (1-5): In the following questions two quantities are given for each question. Compare the numeric value of both the quantities and answers accordingly.
Q1. ‘A’, ‘B’ and ‘C’ together can complete a work in 48 days if they work alternatively. ‘A’ is 25% more efficient than ‘B’ who isless efficient than ‘C’. Quantity I: Difference between days taken by ‘A’ alone and ‘C’ alone to complete the work. Quantity II: Days in which ‘A’, ‘B’ and ‘C’ together can complete half of the work.
Q2. Neeraj invested Rs. X in two different schemes ‘A’ and ‘B’ equally. Scheme A offers 10% p.a. at S.I and scheme B offers 20% p.a. at C.I. After 2 years he got total Rs.2560 interest from both the schemes. Quantity I: Value of ‘X’ Quantity II: Rs. 7200
Q3. Three partners invested capital in the ratio 2 : 7 : 9. The time period for which each of them invested was in the ratio of the reciprocals of the amount invested.. Quantity I: Profit share of the partner who brought in the highest capital if the profit is Rs. 1080 Quantity II: Profit share of the partner who brought in the lowest capital if the profit is Rs. 1080
Q4. X started from a point A towards point B. After 2 hours. Y started from B towards A. By the time X travelled one-fifth of the total distance, Y had also travelled the same. Y’s speed is thrice of that of X’s speed. Quantity I: Difference in time (in hours) taken by X and Y to reach their respective destinations. Quantity II: 12 hours
Q5. A vessel contains 2.5 litres of water and 10 litres of milk. 20% of the contents of the vessel are removed. To the remaining contents, x litres of water is added to reverse the ratio of water and milk. Then y litres of milk is added again to reverse the ratio of water and milk. Quantity I: Value of ‘y’ Quantity II: Value of ‘x’
Q6. A shopkeeper buys 144 items at 90 paise each. On the way 20 items are broken. He sells the remainder at Rs. 1.20 each. His gain per cent correct to one place of decimal is
Q7. The ratio of the number of boys and girls in a school is 2 : 3. If 25% of the boys and 30% of the girls are scholarship holders, the percentage of the school students who are not scholarship holders is
Q8. A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours and 30 minutes. The speed of the boat in still water is
Q9. A takes three times as long as B and C together to do a job. B takes four times as long as A and C together to do the work. If all the three, working together can complete the job in 24 days, then the number of days, A alone will take to finish the job is
Q10. 20 litres of a mixture contains 20% alcohol and the rest water. If 4 litres of water be mixed in it, the percentage of alcohol in the new mixture will be
Directions (11-15): In these questions, two equations numbered I and II are given. You have to solve both the equations and give answer:
Q11. I. x² – 9x + 18 = 0
II. 5y² – 22y + 24 = 0
x² – 6x – 3x + 18 = 0
x (x – 6) –3 (x -6) = 0
(x – 3) (x – 6) = 0
x= 3, 6
II. 5y² – 22y + 24 = 0
5y² – 10y – 12y + 24 = 0
5y (y- 2) –12 (y – 2) = 0
(y – 2) (5y – 12) = 0
y=2, 12/5
∴ x > y
Q12. I. 6x² + 11x + 5 = 0
II. 2y² + 5y + 3 = 0
6x² + 6x + 5x + 5 = 0
6x (x + 1) + 5 (x + 1) = 0
(x+ 1) (6x +5) = 0
x = -1,-5/6
II. 2y² + 5y + 3 = 0
2y² + 2y + 3y + 3 = 0
2y (y+ 1) + 3 (y+ 1) = 0
(y+ 1) (2y + 3) = 0
y= -1,-3/2
∴x≥y
Q13. I. x² + 10x + 24 = 0
II. y² – √625=0
x² +6x + 4x + 24 = 0
x (x + 6) +4 (x+ 6) = 0
(x + 4) (x + 6) = 0
x = –4, –6
II. y² – √625=0
y²=√625
y²=25;
y= ±5
∴ Relationship between x and y cannot be determined
Q14. I. 10x² + 11x + 1 = 0
II. 15y² + 8y + 1 = 0
10x² + 10x+ x+ 1 = 0
10x (x + 1) + 1 (x + 1) = 0
(x + 1) (10x + 1) = 0
x= -1,-1/10
II. 15y² + 8y + 1 = 0
15y² +5y + 3y + 1 = 0
5y (3y + 1) + 1 (3y+ 1) = 0
(3y + 1) (5y + 1) = 0
y=-1/3,-1/5
∴ Relationship between x and y cannot be determined
Q15. I.15x² – 11x + 2 = 0
II. 10y² – 9y + 2 = 0
15x² – 5x – 6x + 2 = 0
5x (3x – 1) – 2 (3x – 1) = 0
(3x – 1) (5x – 2) = 0
x=1/3,2/5
II. 10y² – 9y + 2 = 0
10y² – 5y – 4y + 2 = 0
5y (2y – 1) –2 (2y – 1) = 0
(2y – 1) (5y - 2) = 0
y = 1/2,2/5
∴ x ≤ y