Quantitative Aptitude Quiz For FCI 2022- 10th September

Directions (1-5) Line graph given below gives information about total no. of students appeared in SSC exam held on five different days (Day1, Day2, Day3, Day4 & Day5).

Q1. If no. of student who appeared on day 1 for SSC exam are 5% of total no. of students who applied for SSC exam, then find no. of students who appeared on day 4 for SSC exam are what percent of total no. of students who applied for SSC exam?
(a) 4⅙%
(b) 4⅓%
(c) 2%
(d) 3%
(e) 4.67%

Q2. If ratio of no. of girls to boys appeared on day 2 and day 3 for SSC exam are 3:2 and 5:3 respectively, find no. of girls appeared on day 3 for SSC exam are how much more/less than no. of boys appeared on day 2 for SSC exam?
(a) 2000
(b) 2500
(c) 3700
(d) 5000
(e) 2800

Q3. No. of students appeared on day 1 for SSC exam are what percent more or less than no. of students appeared on day 4 for SSC exam?
(a) 20%
(b) 12.5%
(c) 25%
(d) 14.28%
(e) 7.14%

Q4. What is the ratio of average no. of student appeared for SSC exam on day1, day2 and day5 to that of on day3 and day4?
(a) 147:110
(b) 55:49
(c) 49:55
(d) 55:51
(e) None of these.

Q5. Difference between no. of students appeared for SSC exam on day 1 and day 3 is 12.5% of total no. of students applied for SSC exam. Find total no. of students applied for SSC exam are how much more than no. of students appeared on day 2 for SSC exam?
(a) 75000
(b) 71000
(c) 81000
(d) 80000
(e) 85000

Directions (6-10): – What will come in place of (?) question mark in the following questions?

Q8. ?=225÷45÷0.5×75
(a) 250
(b) 750
(c) 500
(d) 150
(e) 900

Q9. 70% of 500-200%of74+12×15-382=?
(a) 1
(b) -2
(c) -1
(d) 0
(e) 2

Q10. 12³-10800÷36+?=11³
(a) -98
(b) -95
(c) -100
(d) -92
(e) -97

Directions (11 – 15): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and answer the following questions.
(a) x > y
(b) x < y
(c) x ≥ y
(d) x ≤ y
(e) x = y or no relation.

Q11. I. 2x² – 17x + 36 = 0
II. 2y² – 19y+ 45 = 0

Q12. I. x² – 25x + 154 = 0
II. y² – 28y + 195 = 0