Directions (1-5): Study the passage given below and answer the following questions.
There are four trains – A, B, C and D. Each train has different length and different speed. Length of train-D is equal to average of length of train – A & C. Train – A is 60m longer than train – C. Ratio of length of train – D to train – B is 3 : 4.
Speed of train-B is equal to sum of speed of train – A and train – D. Speed of train – C is 20% more than speed of train – D. Ratio of speed of train – A to that of train – C is 5 : 4.
Train – C can cross a pole and 240 meters long platform in 6 seconds and 18 seconds respectively.
Note – Speed of all trains is in km/hr. and length of all trains is in meters.
Q1. Find in what time train – D will cross a man who is running at 12 km/hr. in the opposite direction of train?
(a) 9 seconds
(b) 10.5 seconds
(c) 5 seconds
(d) 7.5 seconds
(e) 12 seconds
Q2. Find in what time train – A will cross train – C while running in opposite direction?
(a) 6 (2/3) seconds
(b) 12 (1/2) seconds
(c) 5 (1/3) seconds
(d) 10 seconds
(e) 8 seconds
Q3. Train–D leaves city-X for city-Y and train-B leaves city-Y for city-X. Train-D leaves at 3:00 P.M. and train-B leaves after 5 hours from train-D. If both train meets each other at 11:00 P.M., then find distance between city-X and city-Y.
(a) 890 km
(b) 920 km
(c) 860 km
(d) 930 km
(e) 950 km
Q4. If train-E is 60 meters long than the average length of train-A & B and speed of train-E is 40% more than speed of train-D, then find in what time train-E will cross 100 meters long platform?
(a) 12 seconds
(b) 15 seconds
(c) 20 seconds
(d) 7 seconds
(e) 10 seconds
Q5. If coaches of train-A are added into train-B due to which speed of train-B reduced by 20%, then find in the new speed of train B. (length of engine of train-A is 20m)
(a) 80 km/hr
(b) 180 km/hr
(c) 120 km/hr
(d) 150 km/hr
(e) 250 km/hr
Solutions
Sol (1-5):
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