Quantitative Aptitude Quiz For Bank Mains Exam 2023-31st October

Directions (1-5): A new party XYZ, participated in election in 5 constituencies (A, B, C, D & E). Pie chart shows % distribution of party’s total votes scored by its 5 candidates and line graph shows, % of votes scored by winner candidates out of total votes polled in these 5 constituencies.

Note: All the votes must be calculated in nearest hundreds.

Q1. Candidate of party XYZ is winner from constituency B and defeated runner-up candidate by 7000 votes. None of the candidates from this constituency obtained vote less than 12000, then calculate maximum possible number of candidates from constituency B.
(a) 6
(b) 7
(c) 15
(d) 13
(e) can’t be determined

Q2. Party XYZ wins from constituency C. In constituency E total votes polled are 45000 less than that of constituency C. Find from how many votes the candidate of party XYZ lost in constituency E?
(a) 79500
(b) 91500
(c) 26500
(d) 27000
(e) 0

Q3. Out of constituency A and D, one of the seats was won by party XYZ. In lost constituency their candidate was runner up by 15000 votes. Find maximum possible difference between total votes polled in both of these constituencies.
(a) 50000
(b) 37500
(c) 25000
(d) either (a) or (b)
(e) either (b) or (c)

Q4. In constituencies A & E, both candidates of party XYZ are runner up, and lost by same number of votes. If the votes polled in E is 180000, find approximate number of votes polled in constituency A.
(a) 350000
(b) 365000
(c) 180000
(d) 100000
(e) None of these

Q5.Which of the following condition is never possible?
(i) constituency B and C have equal number of votes polled given that party wins from C.
(ii) candidate of party XYZ lost by 28000 voters from constituency E.
(iii) constituency A and B have equal number of votes polled.
(iv) winner candidate of constituencies B and D got equal number of votes.
(a) only (i)
(b) Only (i) and (iii)
(c) (i), (ii) and (iv)
(d) (i) and (ii)
(e) All of these are possible

Solutions

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