Dear Aspirants,
Quantitative Aptitude Questions for IBPS Clerk Mains 2017
Quantitative Aptitude is a very important section you must prepare if you are aiming for a job in Bank or Insurance sector. So, these 15 questions can help you practice three very important topics of Quant Section.
Directions (1-15): In each of the following questions two equations are given. You have to solve the equations and
Give answer –
(a) if x < y
(b) if x ≤ y
(c) relationship between x andy cannot be determined
(d) if x ≥ y
(e) if x > y
Q1. I. 3x² + 10x + 8 = 0
II. 3y² + 7y + 4 = 0
Q2. I. 2x² + 21x + 10 = 0
II. 3y² + 13y + 14 = 0
Q3. I. x² + x – 12 = 0
II. y² + 2y – 8 = 0
Q4. I. 4x² – 13x + 9 = 0
II. 3y² – 14y + 16 = 0
Q5. I. 8x² + 18x + 9 = 0
II. 4y² + 19y + 21 = 0
Q6. I. 3x² + 16x + 21 = 0
II. 6y² + 17y + 12 = 0
Q7. I. 16x² + 20x + 6 = 0
II. 10y² + 38y + 24 = 0
Q8. I. 8x² + 6x = 5
II. 12y² – 22y + 8 = 0
Q9. I. 17x² + 48x = 9
II. 13y² = 32y – 12
Q10. I. 8x² + 26x + 15 = 0
II. 4y² + 24y + 35 = 0
Q11. I. 6x² + 19x + 15 = 0
II. 24y² + 11y + 1 = 0
Q12. I. 2x² + 11x + 15 = 0
II. 4y² + 22y + 24 = 0
Q13. I. 2x² + 9x + 9 = 0
II. 2y² + 17y + 36 = 0
Q14. I. 5x² + 29x + 20 = 0
II. 25y² + 25y + 6 = 0
Q15. I. 3x² – 16x + 21 = 0
II. 3y² – 28y + 65 = 0
Give answer –
(a) if x < y
(b) if x ≤ y
(c) relationship between x andy cannot be determined
(d) if x ≥ y
(e) if x > y
Q1. I. 3x² + 10x + 8 = 0
II. 3y² + 7y + 4 = 0
Q2. I. 2x² + 21x + 10 = 0
II. 3y² + 13y + 14 = 0
Q3. I. x² + x – 12 = 0
II. y² + 2y – 8 = 0
Q4. I. 4x² – 13x + 9 = 0
II. 3y² – 14y + 16 = 0
Q5. I. 8x² + 18x + 9 = 0
II. 4y² + 19y + 21 = 0
Q6. I. 3x² + 16x + 21 = 0
II. 6y² + 17y + 12 = 0
Q7. I. 16x² + 20x + 6 = 0
II. 10y² + 38y + 24 = 0
Q8. I. 8x² + 6x = 5
II. 12y² – 22y + 8 = 0
Q9. I. 17x² + 48x = 9
II. 13y² = 32y – 12
Q10. I. 8x² + 26x + 15 = 0
II. 4y² + 24y + 35 = 0
Q11. I. 6x² + 19x + 15 = 0
II. 24y² + 11y + 1 = 0
Q12. I. 2x² + 11x + 15 = 0
II. 4y² + 22y + 24 = 0
Q13. I. 2x² + 9x + 9 = 0
II. 2y² + 17y + 36 = 0
Q14. I. 5x² + 29x + 20 = 0
II. 25y² + 25y + 6 = 0
Q15. I. 3x² – 16x + 21 = 0
II. 3y² – 28y + 65 = 0
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