Quantitative Aptitude Quiz For NIACL AO
Q1. A shopkeeper sells goods on 20% profit. When he purchases on 10% more and sells it on 25% profit then he gets Rs. 14 more. What is the initial cost price of goods?
Q2. By selling an article for Rs. 160, a dealer makes 20% loss. Next time, the dealer sold the same article in such a way that he gained 25%. What is the difference between the percentage increase in his selling price and percentage loss made by him earlier?
Q3. A playground is in the shape of a rectangle. A sum of Rs. 1000 was spent to make the ground usable at the rate of 25 paise per sq. m. The breadth of the ground is 50m. If the length of the ground is increased by 20 m, what will be the expenditure in making this ground usable at the same rate?
Breadth = 50 m
Length = 4000/50 = 80 m
New length = 80 + 20 = 100 m
New area = 100 × 50 = 5000 m²
So, expenditure = 5000 × 0.25 = Rs 1250
Q4. The probabilities of solving a problem by three students. A, B and C are 1/2,1/3 and 1/4, respectively. The probability that the problem will be solved, is
Q5. Two trains A and B are running on parallel tracks in the same direction. Train A which is coming from behind takes 50 seconds to cross B completely. One person in train A observes that he crosses train B in 30 seconds. If the speed of the train A and train B is in the ratio of 2: 1, what is the ratio of their lengths?
Directions (6 -10): Two equations I and II are given below. You have to solve these equations and give answer
Q6. I. x²-5 =0
II. 4y²-24y+35 = 0
Q7. I. x²-5x-14=0
II. y²+7y+10 = 0
Q8. I. 2x² + 9x + 9 = 0
II. 2y² + 17y + 36 = 0
⇒ 2x² + 6x + 3x + 9 = 0
⇒ (x + 3) (2x + 3) = 0
⇒ x = –3, –3/2
II. 2y² + 17y + 36 = 0
⇒ 2y² + 8y + 9y + 36 = 0
⇒ (y + 4) (2y + 9) = 0
y = – 4, –9/2
x > y
Q9. I. 5x² + 29x + 20 = 0
II. 25y² + 25y + 6 = 0
⇒ 5x² + 25x + 4x + 20 = 0
⇒ (x + 5) (5x + 4) = 0
⇒ x = –5, –4/5
II. 25y² + 25y + 6 = 0
⇒ 25y² + 15y + 10y + 6 = 0
⇒ (5y + 3) (5y + 2) = 0
⇒ y = – 3/5, –2/5
y > x
Q10. I. 3x² – 16x + 21 = 0
II. 3y² – 28y + 65 = 0
⇒ 3x² – 9x – 7x + 21 = 0
⇒ (x – 3) (3x – 7) = 0
⇒ x = 3, 7/3
II. 3y² – 28y + 65 = 0
⇒ 3y² – 15y – 13y + 65 = 0
⇒ (y – 5)(3y – 13) = 0
⇒ y = 5, 13/3
y > x
Directions (11-15): What should come in place of question mark (?) in the following question?
Q11.
⇒ ? = 1400 - 1335
= 65
Q13. 36.5% of 140 ÷ 12.5% of 80 =?
Q15. 3.5% of 40 + 3.5% of 80 =? % of 10