IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk

IBPS RRB Quantitative Aptitude Quiz

Here, we are providing IBPS RRB Study Plan as there is left not enough time to deal in details. The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude Quiz to help you practice with the best of latest pattern questions.

Directions (1-5): In each of the following questions two equations are given. You have to solve the equations and
Give answer –

Q1. I. 3x² + 16x + 21 = 0

II. 6y² + 17y + 12 = 0

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_3.1

Q2. I. 16x² + 20x + 6 = 0
II. 10y² + 38y + 24 = 0

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_4.1

Q3. I. 8x² + 6x = 5
II. 12y² – 22y + 8 = 0

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_5.1

Q4. I. 17x² + 48x = 9
II. 13y² = 32y – 12

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_6.1

Q5. I. 8x² + 26x + 15 = 0
II. 4y² + 24y + 35 = 0

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_7.1

Directions (6-10): What approximate value will come in place of question mark (?) in the given questions: (You are not expected to calculate the exact value.)

Q6. 619.992 – 134.99 ÷ 14.998 – (9.01)² =?

720

530

650

690

490

Solution:

? = 619.992 – 134.99 ÷ 14.998 – (9.01)² ≈ 620 – 135 ÷ 15 – (9)² ≈ 530

Q7. 449.97 ÷ 15.02 + 208.08 ÷ 8.01 – 16.01 =?

120

100

Solution:

? = 449.97 ÷ 15.2 + 208.08 ÷ 8.01 – 16.01 ≈ 450 ÷ 15 + 208 ÷ 8 – 16

= 30 + 26 – 16 = 30 + 10 = 40

Q8.

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_9.1

Q9. ? % of (140.06 × 7.99 – 679.92) = 330.01

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_10.1

Q10. 40% of 859 + 87.89 ÷ 7.99 =?

398

286

412

215

355

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_11.1

Directions (11-15): The following bar graph shows the total number of management students from 5 different universities who attended a seminar organized by IIM Ahamadabad in year 2017. Study the graph and answer the questions that follows:

Q11. What is the average number of boys who participated in the seminar?

6,600

6,400

6,250

6,845

6,125

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_13.1

Q12. The number of boys from AKTU who participated in seminar is what percent of number of girls from Indraprasth university who participated in seminar?

120%

160%

150%

130%

100%

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_14.1

Q13. What is the difference between average number of boys from all five universities together and average number of girls from all five universities together who attended the seminar?

2,750

2,800

2,850

2,500

2,150

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_15.1

Q14. What is the ratio of number of girls from LPU and AKTU together to the number of girls from DU and BBD together who attended the seminar?

7 : 5

5 : 7

9 : 11

11 : 9

3 : 7

Solution:

IBPS RRB 2019 Prelims Quantitative Aptitude: PO/Clerk | 27th July |_16.1

Q15. The number of boys who attended the seminar from DU and AKTU together is approximately what percent more or less than the number of girls from AKTU and Indraprasth together who attended the seminar?

55% less

55% more

50% more

52% less

50% less

Solution: