Quantitative Aptitude Quiz For SBI Clerk
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Directions (1-5): study the line graph given below and answer the given questions based on it.
Q1. Downstream speed of boat in Ganga is what percent of downstream speed of boat in Tatpi?
Q2. What will be total time taken by boat to go to a distance 28 km from a point A to B and returning from B to A in Yamuna ? (River is flowing from A to B)
Q3. What is the average of speed of boat in still water in all the rivers together?
Q4. What is the ratio between downstream speed in Narmada to upstream speed in Yamuna?
Upstream speed of boat in Yamuna = 12-2 = 10 km/hr
Required average =10/10=1∶1
Q5. In which river swimming will be easiest compare to other against the current>
Hence, the required river will be Yamuna
Q6. The radius of a circular field is equal to the side of a square field. If the difference between the perimeter of the circular field and that of the square field is 32m, what is the perimeter of the square field? (in metere)
Q7. The outer circumference of a 1 cm thick pipe is 44 cm. How much water will 7 cm of the pipe hold?
(take π=22/7)
Q8. A bag has twelve strawberry out of which four are rotten. Two strawberry are selected at random. Find the probability that the strawberry are of both types.
Q9. Two dice are thrown. The probability that both of them show an even number greater than 4 is:
= 1/36
Q10. In a class, there are 15 girls and 10 boys. Three students are selected at random. The probability that only girls or only boys get selected is:
Directions (11-15): In the following questions, two equations in x and y are given. Solve these equations and give answer
Q11. I. x² + 7x + 12 = 0
II. 4y ² = 36
⇒ x = –3, –4
II. y² = 9
⇒ y = ± 3
y ≥ x
Q12. I. 2x ² +5x + 3 = 0
II. y ² + 3x + 2 = 0
⇒ 2x² + 2x + 3x + 3 = 0
⇒ (x + 1) (2x + 3) = 0
⇒ x = -1, -3/2
II. y² + 3y + 2 = 0
⇒ (y + 1) (y + 2) = 0
⇒ y = –1, –2
No relation
Q13. I. 2x + 3y = 5
II. 3x + 2y = 10
Q14. I. x² + 19x + 84 = 0
II. y² + 14y + 49 = 0
⇒ (x + 7) (x+ 12) = 0
⇒ x = -7, –12
II. y² + 14y + 49 = 0
⇒ (y + 7) ² = 0
⇒ y = –7
y ≥ x
Q15. I. 3x² + 4x + 1 = 0
II. 2y² + 3y + 1= 0
⇒ 3x² + 3x + x +1 = 0
⇒ (x + 1) (3x +1) = 0
⇒ x = -1, -1/3
II. 2y² + 3y + 1= 0
⇒ 2y² + 2y + y +1 = 0
⇒ (y + 1) (2y+ 1) = 0
⇒ y= -1,-1/2
No relation
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