Here, we are providing free crash course for LIC AAO Mains as there is left not enough time to deal in details. The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.
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Q1. The sum of four numbers is 64. If you add 3 to the first number, 3 is subtracted from the second number, the third is multiplied by 3 and the fourth is divided by three, then all the results are equal. What is the difference between the largest and the smallest of the original numbers?
32
27
21
Cannot be determined
None of these
Solution:
Q2. Ms. Pooja Pushpan invests 13% of her monthly salary, i.e. Rs. 8554 in mediclaim Policies. Later she invests 23% of her monthly salary on Child Education Policies. Also, she invests another 8% in her monthly Funds. What is the total monthly amount invested by Ms. Pooja Pushpan?
Rs. 28952
Rs. 43428
Rs. 347424
Rs. 173712
None of these
Solution:
Q3. The batting average of 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded the average of the remaining 38 innings is 48. His highest score was:
172
173
174
176
None of these
Solution:
Let the highest score be x
∴ 40 × 50 = 38 × 48 + x + x – 172
⇒ 2000 = 1824 + 2x - 172
⇒ x = 174 runs.
Q4. A vessel contains liquid P and Q in the ratio 5 : 3. If 16 L of the mixture are removed and the same quantity of liquid Q is added, the ratio become 3 : 5. What quantity does the vessel hold?
35 L
45 L
40 L
50 L
None of these
Solution:
Q5. Several litres of acid were drawn off a 54 L vessel full of acid and an equal amount of water added. Again, the same volume of the mixture 2 was drawn off and replaced by water. As a result the vessel contained 24 L of pure acid. How much of the acid was drawn off initially?
12 L
16 L
18 L
24 L
None of these
Solution:
Directions (6 – 10): Study the following pie chart and bar graph carefully to answer the following questions.
The pie chart shows the percentage distribution of aspirants who have applied for various exams. The bar graph shows the vacancy in these exams.
Q6. Average of all aspirants who have applied for various given exam is approximately how many times the total no. of vacancies?
39
32
35
38
41
Solution:
Q7. If Railways reduces two-fifth of its vacancies, then total vacancies will be reduced by how much percent?
13.56%
14.56%
18.2%
17%
None of these
Solution:
Q8. What will be the difference between average number of aspirants per post in SSC and the average number of aspirant per post in IBPS?
56
41
45
52
48
Solution:
Q9. If no. of vacancies of IBPS increased by 10% and for one final selection in all the given vacancies three aspirants would be rejected during interviews. Find no. of aspirant qualified for Interview for IBPS is approximately how many times the no of aspirant qualified for PSUs and KVS interviews both?
3
3.5
5
4.5
2
Solution:
As per given statement, clearly For one post, 4 will selected for Interviews
No. of posts/ vacancies in IBPS now = 9500 + 950 = 10450
∴ No. of aspirant qualifies for IBPS interview = 10450 × 4 = 41800
No. of aspirants qualifies for PSUs and KVS interviews = (2800 + 700) × 4 = 14000
Desired value = 41800/14000 ≈ 3 times
Q10. Out of all vacancies allocated, 15% of the selected aspirants didn’t join. Hence 8% of the IBPS and 10% of Railways vacancies remain unfilled. What will be the approximate value of ratio between total vacancies remain unfilled for IBPS and Railways together to Rest of the organizations vacancy which remain unfilled.?
5 : 7
4 : 5
5 : 9
9 : 11
11 :13
Solution:
Directions (11-15): What will come in place of question mark (?) in the following simplification problems?
Q11.
Solution:
Q12. 36% of 545 + 32% of 215 – 47% of 1300 = ?
643
346
-411
-346
436
Solution:
Q13.
1170
1730
1510
1710
1150
Solution:
? = 35 ÷ 7 × 342 = 1710
Q14.
9110
9120
8510
9620
8120
Solution:
48 ÷ 3 × 570 = ?
Or, ? = 9120
Q15.
3
4
5
2
1
Solution:
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