Quantitative Aptitude Quiz For IBPS PO/Clerk Prelims
Directions (1-5): Study the following information given below carefully and answer the related questions asked.
In a company, there are four departments namely Blog, content, support & Video. Out of total employees, 100/3 % are working in blog team and 25% of remaining are working in support team. Number of employees working in content team are 20% more than that in Blog team. 24 employees are working in video team. 40% of employees working in blog team are from Delhi NCR. 60% of employees working in support team are from North-East. 75% of total employees working in content department come from East of India. The employees working in Video department are either from Haryana or from Delhi NCR, and they are in the ratio of 3:5. No employee working in content and support team belongs to Delhi NCR.
Q1. Total number of employees working in blog team are what percent more or less than the total number of employees working in video team?
Q2. What is the ratio of employees who comes from Delhi NCR to the total employees working in content team?
Q3. What is the average of total number of employees working in Blog team, support team and Video team together?
Q4. If 12 ½% employee of content team, 16 ⅔% employees of video team and 20% employees of support team are over age for banking exams then find the number of such employees who cannot be a banker.
Q5. Total number of employees coming from Delhi NCR who works in blog team and number of employees coming from North-East who works in support team together are how many (in number) more or less than the number of employees coming from East region of India, working in content team?
Directions (6 -10) Simplify the following questions and find the value of (?).
Q6. 5431 + 4687 – 8462 =?
Q7. 31% of 500+ 41% of 1100 – 50% of 790 = ?
= 606 – 395 = 211
Q8. 1107 ÷ 9 × 6 + 236 – 874 = ?
Directions (11 -15): Two equations I and II are given below. You have to solve these equations and give answer
Q11. I. 8x² + 6x = 5
II. 12y² – 22y + 8 = 0
⇒ 8x² + 10x – 4x – 5 = 0
⇒ (4x + 5) (2x – 1) = 0
⇒ x = ½, –5/4
II. 12y² – 22y + 8 = 0
⇒ 6y² – 11y + 4 = 0
⇒ 6y² – 3y – 8y + 4 = 0
⇒ (2y – 1) (3y – 4) = 0
⇒ y = 1/2, 4/3
y ≥ x
Q12. I. 17x² + 48x = 9
II. 13y² = 32y – 12
⇒ 17x² + 51x – 3x – 9 = 0
⇒ (x + 3) (17x – 3) = 0
⇒ x = 3/17, – 3
II. 13y² – 32y + 12 = 0
⇒ 13y² – 26y – 6y + 12 = 0
⇒ (y – 2) (13y – 6) = 0
⇒ y = 2, 6/13
y > x
Q13. I. 8x² + 26x + 15 = 0
II. 4y² + 24y + 35 = 0
⇒ 8x² + 20x + 6x + 15 = 0
⇒ 4x (2x + 5) + 3(2x + 5) = 0
⇒ (2x + 5) (4x + 3) = 0
⇒ x = – 5/2, –3/4
II. 4y² + 24y + 35 = 0
⇒ 4y² + 10y + 14y + 35 = 0
⇒ 2y (2y + 5) + 7 (2y + 5) = 0
⇒ (2y + 5) (2y + 7) = 0
⇒ y = –5/2, –7/2
x ≥ y
Q14. I. 6x² + 19x + 15 = 0
II. 24y² + 11y + 1 = 0
⇒ 6x² + 9x + 10x + 15 = 0
⇒ (2x + 3) (3x + 5) = 0
⇒ x = –3/2, –5/3
II. 24y² + 11y + 1 = 0
⇒ 24y² + 8y + 3y + 1= 0
⇒ (3y + 1) (8y + 1) = 0
⇒ y = –1/3, –1/8
y > x
Q15. I. 2x² + 11x + 15 = 0
II. 4y² + 22y + 24 = 0
⇒ 2x² + 6x + 5x + 15 = 0
⇒ (x + 3) (2x + 5) = 0
⇒ x = – 3, –5/2
II. 4y² + 22y + 24 = 0
⇒ 2y² + 11y + 12 = 0
⇒ 2y² + 8y + 3y + 12 = 0
⇒ (y + 4) (2y + 3) = 0
⇒ y = –4, –3/2
No relation